Answers to Second Exam


Form A (11 am)
Form B (11 am)
Form C (1 pm)
1
a) -1/4
b) -infty, DNE
a) -1/3
b) -infty, DNE
a) -infty, DNE
b) -1/4
2
a) 8x
b) 4x^2, 8x
a) 10x
b) 5x^2, 10x
a) 4x
b) 2x^2, 4x
3
[(2x)(8x+3)-(4x^2+3x)(2)]
over 4x^2
[(2x)(10x+4)-(5x^2+4x)(2)]
over 4x^2
(3/2)sqrt(x) - 6/x^3
4
(3/2)sqrt(x) - 28/x^5
(5/2)x^(3/2) - 14/x^3
[(2x)(12x^2-7)-(4x^3-7x)(2)]
over 4x^2
5
-12 csc^3(4x) cot(4x) -6 cot^2(2x) csc^2(2x)
4x^5 tan^3(x) sec^2(x)
+ 5x^4 tan^4(x)
6
4x^5 sin^3(x) cos(x)
+ 5x^4 sin^4(x)
4x^6 sin^3(x) cos(x)
+ 6x^5 sin^4(x)
-12 cos^2(4x) sin(4x)
7
240x^3(7x^3+4x)^15(5x^4-8)^11 +
15(21x^2+4)(7x^3+4x)^14(5x^4-8)^12
300x^3(9x^3+4x)^12(5x^4-8)^14 +
12(27x^2+4)(9x^3+4x)^11(5x^4-8)^15
280x^3(2x^3+4x)^11(5x^4-3)^13 +
11(6x^2+4)(2x^3+4x)^10(5x^4-3)^14
8
-5/2 and 1/3
-5/2 and 1/3 -3/2, 2/5
9
a) (3x^2y)/(2y-x^3)
b) y-3=(9/5)(x-1)
a) (3x^2y)/(2y-x^3)
b) y-3=-18(x-2)
a) (2x-y^3)/(3xy^2+6)
b) y-1=(1/3)(x-3)
10
33.35 PI, increasing
8.32 PI, increasing
-37.95 PI, decreasing
11
a) polys are cont's and diff'ble
b) (y(2)-y(0))/(2-0)=-12
c) -32t+20=-12 so t=1
a) polys are cont's and diff'ble
b) (y(2)-y(0))/(2-0)=-12
c) -32t+20=-12 so t=1
a) polys are cont's and diff'ble
b) (y(2)-y(1))/(2-1)=-28
c) -32t+20=-28 so t=1.5